Construct a rhombus, the lengths of whose diagonals are 7 cm and 9 cm. Construct a rhombus with side 4.2 cm and one of its angles equal to 65 o . Construct a rhombus with the length of one of its sides as 4 cm and one of the angles as 60o Construct a rhombus the lengths of whose diagonals are 6cm and 8cm. Class-VIII . Maths . Practical Geometry . Rajesh sattigeri. Jan 12, 2014. Construct a rhombus the lengths of whose diagonals are 6cm and 8cm. Construct a rhombus the lengths of whose diagonals are 6cm and 8cm person. Syeda. Answer. Steps of Construction: 1) Draw a line.

Let's construct it . Steps of construction 1. Draw diagonal AC of length 6 cm 2. Drawing perpendicular bisector of AC With A as center, and radius more than half AC, draw an arc on top and bottom of AC Now with D as center, and same radius, draw an arc on top and bottom of AC 3 Construct a parallelogram, one of whose sides is 4.4cm and whose diagonals are 5.6cm and 7cm. measure the other side. asked May 5, 2020 in Constructions by Varun01 ( 53.5k points) construction

PQRS is the required **rhombus** with **the** **diagonals** **of** **lengths** **6** **cm** **and** **7** **cm.** Note that O is the mid-point of the two **diagonals** **and** ∠POQ = ∠QOR = ∠ROS = ∠SOP = 90 degrees. To learn more about **rhombus**, click on the linked article Construct a rhombus whose diagonals are 4cm and 6cm in lengthRs Aggarwal Class 9 Exercise 13 Example 13Triangle full concept with propertieshttps://youtu.be/.. I never teach my pupils. I only attempt to provide the conditions in which they can learn.- Albert EinsteinEducational FREE Website: http://www.foundation4ii.. Transcript. Ex 4.2, 1 (iii) Construct the following quadrilaterals. Rhombus BEND BN = 5.6 cm DE = 6.5 cm Here, we are given a rhombus with both diagonals To construct it, we will use property of rhombus In rhombus, Diagonals are perpendicular bisectors of each other So, our figure will look like Here, BN is the perpendicular bisector of ED So, BN ⊥ ED and O is the mid-point of ED and BN.

Steps of Construction: 1) Draw a line segment say AC = 6 cm 2) With A as centre draw an arc of length equal to half of 8 cm ie., 4 cm below AC 3) With C as centre draw another ar 1) Join points L, I, F and T to complete rhombus LIFT 2) Draw perpendicular bisector of segment LF which will intersect segment LF at point O. 3) Taking O as centre and radius of 2 1 0 = 5 c m, draw arcs on both sides of segment LF to intersect perpendicular bisector in I and T respectively. 4) Draw segment LF of length 6 cm as base of rhombus Construct a rhombus MORE from following dimensions-M R = 6 c m and O E = 8 c m Following are the steps given to construct rhombus MORE. Arrange them in proper order-1) Draw perpendicular bisector of segment MR which will intersect segment MR at point O. 2) Draw segment MR of length 6 cm as base of rhombus. 3) Join points M, O, R and E to.

Construct a rhombus whose diagonals are 1 6 cm and 1 2 cm. What property of the diagonals is used? Easy. View solution. Rhombus BEST BE = 6.5 cm ET = 8 cm. Medium. View solution. State whether true or false: We can construct a rhombus if both its diagonals are known. Easy. View solution. View more. Learn with content. Watch learning videos. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps. Draw the diagonal say AC = 4 cm Taking A and C as centres and radius more than ½ AC draw arcs on both sides of the line segment AC to intersect each other Using ruler and compasses only, construct a rhombus whose diagonals are 8 cm and 6 cm. Measure the length of its one side Transcript. Ex 4.5, 2 Draw the following. A rhombus whose diagonals are 5.2 cm and 6.4 cm long. Here, we are given a rhombus with both diagonals To construct it, we will use property of rhombus In rhombus, Diagonals are perpendicular bisectors of each other So, our figure will look like Here, BD is the perpendicular bisector of AC So, BD ⊥ AC and O is the mid-point of AC and BD ∴ OD = OB. Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal. CBSE CBSE Class 8. Textbook Solutions 5345. Question Bank Solutions 4852. Concept Notes & Videos 227. Syllabus. Advertisement Remove all ads. Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal. - Mathematics. Answer in Brief.

* Construct a triangle whose sides are 3*.6 cm , 3.0 cm and 4. 8 cm. Bisect the smallest angle and .measure each part. asked Feb 2, 2018 in Class IX Maths by aman28 ( -872 points) constructio Construct a rhombus whose one side is 4.5 cm and one diagonal is 5 cm. View solution Construct a rhombus of side 6 c m and one diagonal of length 1 0 c m Steps of construction: Step 1: Draw AB = 3. 6 cm. Construct a rhombus the lengths of whose diagonals are 6 cm and 8 cm. Answer: We know that the diagonals of a rhombus bisect each other. All the sides of a rhombus are equal in length. The diagonals of a rhombus intersect at 90.

To construct a rhombus whose side is of length 3.4 cm and one of its angle is 45°, use the following steps 1.Draw a line segment AS of length 3.4 cm. 2.Now, generate an angle 45° at both ends A and B of line segment AB and plot the parallel lines AX and BY. 3.Cut AD and SC of length 3.4 cm from AX and BY, respectively * Related Questions*. construct quadrilateral PQRS in which PQ= 7cm, PR=PS = 5.5cm, RS =4.5 cm and RQ=4-5cm? How to construct a kite when 4 sides are given and one long. Steps of construction 1. Draw AI = 6 cm 2. Draw ray AX such that ∠IAX = 110° and draw IY such that ∠AIY = 70°. 3. With A and I as centres and radius 6cm draw arcs intersecting AX and IY at P and R respectively. 4. Join PR. Thus, PAIR is the required rhombus. Example 35 : One of the diagonals of a rhombus and its sides are equal Click hereto get an answer to your question ️ Construct a rhombus whose diagonals are 16 cm and 12 cm. What property of the diagonals is used? O is the intersection of the diagonals. Then the length of O C + O B is : MEDIUM. View Answer. Construct Q S are 8 cm and 6 cm respectively. Find by construction a point X equidistant from.

- Draw a line AB of 10 cm in length. Taking A as center draw two arcs of any radius r > 5 cm one above and one below the line AB Repeat taking B as center draw another two arcs of the same radius r as above Let arcs above AB intersect at P and the a..
- Construct a rhombus whose diagonals are 4 cm and 6 cm in length. Measure each side of the rhombus
- Given : Rhombus with diagonals length = 4 cm, 6 cm. Steps of Construction : 1. Draw a line AB = 4 cm. 2. Bisect the AB using another line EF which intersects it at point X . E X F is perpendicular to AB. 3. As center X mark an arc of 3 cm as the radius on XF and XE which intersects at C and D respectively. 4. Join AD, AE, BC, BD. ACBD is the.
- We know that, all sides of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps. 1.Draw the diagonal say AC = 4 cm 2.Taking A and C as centres and radius more than ½ AC draw arcs on both sides of the line segment AC to intersect each other. 3.Cut both arcs intersect.
- Note: Here we have chosen length of 2.5 cm because in Rhombus diagonals bisect each other at point of intersection. Since length of other diagonal is 5 cm (as given), so half of 5 cm is 2.5 cm Step 5: Use ruler and join points P & S, P & Q, S & R and R & Q
- I want to do a quick argument or proof as to why the diagonals of a rhombus are perpendicular so remember a rhombus is just a parallelogram where all four sides are equal in fact if all four sides are equal it has to be a parallelogram and just to make things clear some rhombuses of squares but not all of them because you could have a rhombus like this that comes in that where the angles aren.
- Using ruler and compasses only, construct a rhombus whose diagonals are 8 cm and 6 cm. Measure the length of its one side. Solution: Selina Concise Mathematics Class 8 ICSE Solution

- Diagonal Can a rhombus have the same length diagonal and side? Construction Construction the triangle ABC, if you know: the size of the side AC is 6 cm, the size of the angle ACB is 60° and the distance of the center of gravity T from the vertex A is 4 cm. (Sketch, analysis, notation of construction, construction) Medians 2:
- With D as centre and radius equal to 6 cm cut on arc drawn in step-4 at point G. A rhombus whose diagonals are 5.2 cm and 6.4 cm long. It may be the included angle between the sides or one of the diagonals to construct a unique quadrilateral. So, the required parallelogram cannot be drawn. STUDY MATERIAL FOR CBSE CLASS 8 MATH.
- 16. Using ruler and compasses only, construct a rectangle each of whose diagonals measures 6cm and the diagonals intersect at an angle of 45°. Solution. Steps of construction: (i) Draw a line segment AC = 6cm (ii) Bisect AC at O. (iii) At O, draw a ray XY making an angle of 45 o at O. (iv) From XY, cut off OB = OD = 6/2 = 3cm each (v) Join AB.
- Get RS Aggarwal Solutions for Class 8 Chapter Construction Of Quadrilaterals here. BeTrained.in has solved each questions of RS Aggarwal very thoroughly to help the students in solving any question from the book with a team of well experianced subject matter experts. Practice Construction Of Quadrilaterals questions and become a master of concepts

** (iv) AB = 5**.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm. (v) diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°. (vi) lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45° Question. 188 **Construct** **a** **rhombus** **whose** side is 5 cm and one angle is of 60° Solution. Question. 189 **Construct** **a** rectangle whose one side is 3 cm and a **diagonal** is equal to 5 cm. Solution. Question. 190 **Construct** **a** square of side 4 cm. Solution. Question. 191 **Construct** **a** **rhombus** CLUE in which CL = 7.5 cm and LE = **6** **cm.** Solution In rhombus SAME, AT = 7cm and TM = 5cm. Find its area. answer choices Find the length of a diagonal of a kite whose area is 176 sq. cm. and the other diagonal is 16 cm long. answer choices . 22 cm. 6cm, 6cm, 37cm and 37cm. 7cm, 7cm, 36cm and 36cm. Tags: Question 21 . SURVEY . 300 seconds Complete the sentence: The diagonals of a rhombus will always Construct a kite by joining the centre points of the circles to the intersection points of the circles. Draw in the diagonals of the kite. Mark all lines that are the same length Selina solutions for Concise Mathematics Class 8 ICSE chapter 18 (Constructions) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any

- Since diagonals of rhombus divide into four equal triangles. Therefore, Area of rhombus = 4(area of one triangle) = 4. 1 AC BD xx 2 2 2 §· ¨¸ ©¹ = AC x BD d x d A. 12. 22 Area of rhombus = 1 2 (product of two diagonals) Example 7: The length of each side of a rhombus is 120cm and two of its opposite angles are each 60. o. find the area.
- Below is shown a rhombus with the given diagonals. Consider the right triangle BOC and apply the Pythagorean theorem as follows BC 2 = 10 2 + 24 2; and evaluate BC BC = 26 meters. We now evaluate the perimeter P as follows: P = 4 * 26 = 104 meters. Problem 3 The perimeter of a rhombus is 120 feet and one of its diagonal has a length of 40 feet
- Find the length of each diagonal. The diagonals of a rhombus are the lines that connect the opposite vertices (corners) in the center of the shape. The diagonals of a rhombus are perpendicular and form four right triangles through their intersection. Let's say the diagonals are 6 cm. and 8 cm. long
- A rhombus whose diagonals are 4 cm and 6 cm in lengths. Solution: We know that, all sides of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps. Draw the diagonal say AC = 4 c
- 6.8.3 Construction of Rhombus: We have seen that, to construct a parallelogram we need three elements (suitable combination of sides, diagonals and angles). Because of the special property of rhombus, only two elements are enough to construct a rhombus uniquely. 1. Length of two diagonals are given

(d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G. (e) Join GD and GO. It is the required quadrilateral GOLD. (iii) Given: BN = 5.6 cm, DE = 6.5 cm. To construct: A rhombus BEND. Steps of construction: (a) Draw DE = 6.5 cm If the area of rhombus be 24 cm2 and one of its diagonal AC= 4cm. find the perimeter of rhombus. How many bricks of size 22cm x 10cm x 7cm are required to construct a wall 33m long , 3.5 high Find the surface area of a chalk box whose length , breadth and height are 16 cm, 8cm and 6cm respectively Q 37 The lengths of the diagonals AC and BD of a rhombus are 6 cm and 8 cm respectively. Find the length of each side of the rhombus. Q 20 Construct a parallelogram whose two sides and one angle are 4 cm, 5.5 cm and 70° respectively. Q 1 Find the volume of a cuboid whose length is 8 cm, breadth 6 cm and height 3.5 cm. Mark (1 2 21. The quadrilateral whose diagonals are equal and bisect each other at right angle is _____. A) Triangle B) Trapezium C) Rhombus D) Squar Find the perimeter of the rhombus whose side length is 16 cm. Solution : Formula for perimeter of a rhombus : = 4s Substitute 16 for s. = 4(16) = 64. So, the perimeter of the rhombus is 64 cm. Example 2 : If the perimeter of a rhombus is 72 inches, then find the length of each side. Solution : Perimeter of the rhombus = 72 inches. 4s = 7

- Ans- Rhombus is a quadrilateral whose all four sides have equal length. Each angle of Rhombus is equal to 90*. It has four vertices and can have two diagonals of the opposite side, which divides the Rhombus into two equilateral triangles
- Construct a rhombus ABCD, if the size of the diagonal AC is 6 cm and diagonal BD 8 cm long
- g four right triangles, each with legs of 7.5 cm and 4 cm (half each diagonal)

- Note: Since square is also a rhombus having equal diagonals, area of a square = \(\frac{1}{2}\)d 2 Area and Perimeter of a Triangle A triangle is a polygon with three vertices, and three sides or edges that are line segments
- Construct Parallelograms, Squares and Rectangles, Parallel Lines, Triangles, Angles, how to construct a parallelogram given the lengths of its sides and an angle, given the lengths of its diagonals, how to construct a square given the length of the diagonal, given the length of one side, how to construct a rectangle, examples with step by step solutions, using a compass and a straightedge or rule
- calculate the length of the diagonal of a rectangle whose sides are 8cm and 6cm . math. the length of a rectangle is 8cm more than the width and its area is 172cm^2 .Find a) the width od the rectangle; b) the length of the diagonal of the rectangle, giving your answer correct to 2 decimal places . mathematic
- Question:6 Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal. Answer: Rhombus is a type of parallelogram and area of parallelogram is product of base and height. So,Area of rhombus = base height . Let the other diagonal be x . Area of rhombus

where c is the length of the hypotenuse, and a and b are the lengths of the other two sides. What is Pythagorean Theorem? The Pythagorean Theorem states: In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the. Draw a line AB of length 6 cm . Take any point P on it and draw perpendicular at P , on this perpendicular take a point Q on it and from Q draw a perpendicular QR . What can you say about AB and QR. Construct a triangle ABC such that AB= 7cm, BC=5cm, < ABC=600. Construct a triangle PQR such that PQ= 4.5 cm, QR=5cm, RP= 6cm ⇒ a = 6 cm Hence, the side of the cube is 6 cm. Question. 22 Three cubes of metal whose edges are 6 cm, 8 cm and 10 cm respectively, are melted to form a single cube. The edge of the new cube is (a) 12 cm (b) 24 cm (c) 18 cm (d) 20 cm Solution The answer is simplest in terms of half the lengths of the diagonals, namely a = 8.5 and b =16.5. The center of the inscribed circle is the point C where the diagonals intersect. Focus on the upper quarter of the rhombus, which is a right triangle.. Another formula for finding the area of rhombus can be obtained by using the diagonals. Consider the rhombus below: the area of a rhombus is equal to half the product of the length of the diagonals. if you want to construct an inscribed regular hexagon (6 sides), first draw a circle and locate the center of the circle..

- Related math problems and questions: Rhombus construction Construct ABCD rhombus if its diagonal AC=9 cm and side AB = 6 cm. Inscribe a circle in it touching all sides..
- ∠ ADC = 60 ° (Given) ∠ ABC = 60 ° (Opposite angles of a rhombus are equal) Now, consider ADC ∵ AD = CD (Sides of a rhombus) ∵ ∠ DAC = ∠ DCA Angles opposite to equal sides are equal ∠ ADC + ∠ DCA + ∠ CAD = 180 ° (Angle sum property) ⇒ 2 ∠ DCA + 60 ° = 180 ° [From (i)] ⇒ ∠ DCA = ∠ DAC = 60 ° Similarly, ∠ BAC.
- Construct a ∆ABC in which BC = 3.6 cm, AB = 5 cm and AC = 5.4 cm. Draw the perpendicular bisector of the side BC. Construct a right-angled triangle one side of which measures 3.5 cm and the length of whose hypotenuse is 6 cm. The diagonals of a rhombus (a) are always equal (b) never bisect each other.
- How to construct a regular hexagon given one side. The construction starts by finding the center of the hexagon, then drawing its circumcircle, which is the circle that passes through each vertex. The compass then steps around the circle marking off each side. A Euclidean construction
- One diagonal of a rhombus makes a 27 degree angle with a side of the rhombus. If each side of the rhombus is 6.2 inches find the length of each diagonal to the nearest tenth. Geometry. Two sides of a rhombus form a 120º angle. The length of each side is 6 in. Explain how to find the area of the rhombus, and then calculate the area
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Construct a parallelogram POUR in which PO=5.5cm, OU=7.2cm, and L 0=700 Construct a rectangle CARE in which CA = 5.5 cm and AR = 5 m. Construct a square of side 5.6 cm A square also fits the definition of a rectangle (all angles are 90°), a rhombus (all sides are equal length), a parallelogram (opposite sides parallel and equal in length) and a regular polygon(all angles equal and all sides equal). What a hero! Enter the side length, area, diagonal or perimeter and the other values are calculated live

2. The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8cm and 16.5cm respectively. If one of the diagonal of the rhombus is 22cm, find the length of the other diagonal. 3. The floor of a rectangular hall has a perimeter 250m. If the cost of paining the four walls a The diagonals are congruent. The diagonals are perpendicular to and bisect each other. A square is a special type of parallelogram whose all sides and angles are equal. Length of Diagonal = Length Area= (length) 2. Perimeter= 4Xlength. Rhombus: All sides are congruent. Opposite angles are congruent. The diagonals are perpendicular to and bisect. Length ofthe diagonal (BD) = I I cm. Area ofquadrilateral = Area of Rhombus x 12 x 11- area ofa rhombus is halfthe product of its diagonals. the area ofa rhombus whose diagonals are oflength I O cm and 8.2 cm. Exa pe : olutio . lengths ofperpendiculars from B and D on AC be 5 cm and 6 cm respectively

Length of Diagonal = Length Area= (length) 2. Perimeter= 4Xlength . Rhombus: All sides are congruent. Opposite angles are congruent. The diagonals are perpendicular to and bisect each other. Adjacent angles are supplementary. A rhombus is a parallelogram whose diagonals are perpendicular to each other. Area = (aXb)/2 Perimeter= 4 X length construct a rhombus whose diagonals are 6cm , 8cm. Share with your friends. Share 8 Draw the bigger diagonal (Length=8cm using this pt and centre) Find the lenght of each side of a rhombus whose diagonals are of lenght 6cm and 8cm. 0 ; construct a rhombus the lengthsof whose diagonals are 6cm and 8cm. Q 14 Construct a rhombus with side 4.5 cm and one diagonal 6 cm. Marks (3) Q 15 Construct the quadrilateral ABCD with AB = 4 cm, BC = 6 cm, CD = 5.5 cm, AD= 5 cm and. Construct a parallelogram, one of whose sides is 4.4 cm and whose diagonals are 5.6 cm and 7 cm. Measure the other side. Solution: Steps of Construction : We know that diagonals of a parallelogram bisect each other. (i) Draw a line segment AB = 4.4 cm. (ii) With centre A and radius 5.6 2 cm and with centre B and radius 7 2 = 3.5 cm. draw arc

Construct the centroid of Ø PQR whose sides are PQ = 8 cm, QR = 6 cm, RP = 7 cm. Solution: Side = 6.5 cm Construction: Step 1 : Draw ∆ABC with AB = BC = CA = 6.5 cm Step 2 : Construct angle bisectors of any two angles (A and B) and let them meet at 1.1 is the incentre of ∆ABC 1. Draw a rectangle of diagonal 9 cm and angle between the diagonal and one side is 30°. Mark a point on the diagonal at a distance 6 cm from one end of the diagonal. Draw lines perpendicular to the sides of the rectangle through this point. Erase unwanted parts, we get the required pattern. 2. Construct an equilateral triangle with side 3 cm Explanation: . To find the value of diagonal , we must first recognize some important properties of rhombuses.Since the perimeter is of is , and by definition a rhombus has four sides of equal length, each side length of the rhombus is equal to .The diagonals of rhombuses also form four right triangles, with hypotenuses equal to the side length of the rhombus and legs equal to one-half the. Construct a rectangle such that one diagonal is 6-6 cm and the angle between two diagonals is 120°. Solution: Question 9. Construct a rhombus whose one side is 5 cm and one angle is 45° Solution: Question 10. Construct a rhombus whose one side is 4·5 cm and one diagonal is 5 cm. Solution: Question 11 106 kite adjacent rhombus Square All sides are the same length. All angles are 90°. The diagonals are equal in length and bisect each other at right angles. It has 4 lines of reﬂ ection symmetry. It has rotational symmetry of order 4. Rectangle Opposite sides are the same length. All angles are 90°. The diagonals are equal i

A rhombus is a special type of quadrilateral parallelogram, where the opposite sides are parallel and opposite angles are equal and the diagonals bisect each other at right angles. There are many ways to calculate its area such as using diagonals, using base and height, using trigonometry, using side and diagonal If he takes the diagonal AC first, then the construction of ∆ACP and ∆ABC is not possible as the data are insufficient. Question 2. We saw that 5 measurements of a quadrilateral can determine a quadrilateral uniquely Construct a parallelogram, one of whose sides is 5.5 cm and whose diagonals are 5.8 cm and 7 cm. 8. Construct a parallelogram whose diagonals are 5.6 cm and 6.8 cm, and an angle between them is 50

Construct an angle at Q equal to \(\angle\)AOB. Steps of construction. Fron the point Q, draw a line segment QP. With centre at O and suitable radius draw an arc to intersect OA at C and OB at D A rhombus refers to a quadrilateral having two simultaneous characteristics: sides are all equal AND the opposite sides are parallel. Please note that a rhombus having four right angles is actually a square. How does this rhombus calculator work? Depending on the figures you know this rhombus calculator can perform the following calculations Draw AB = 6 cm. with A as Center and radius = 10 cm draw an arc ( circle ) With B as Center and radius = 6 cm draw an arc (circle) meeting point of two arcs is C. AC becomes Diagonal. AB and BC are sides . Draw the other side on the opposite side of Diagonal. you will get rhombus This page shows how to construct an equilateral triangle with compass and straightedge or ruler. It begins with a given line segment which is the length of each side of the desired equilateral triangle. It works because the compass width is not changed between drawing each side, guaranteeing they are all congruent (same length). It is similar to the 60 degree angle construction, because the. iii) We know that the diagonals of a rhombus always bisect each other at \(90^{\circ}\).Let us assume that these are intersecting each other at a point O in this rhombus. Hence EO=OD=3.25. A rough sketch of the rhombus can be drawn as follows: 1) Draw a line segment MN of 5.6 cm and also draw its perpendicular bisector

10. Construct a square, each of whose diagonals measures 5.6 cm. Solution: Steps of Construction: Given that a square, each of whose diagonals measures 5.6 cm. 1. Draw a line segment of length 5.6 cm and mark the ends as P and R. 2. Bisect the line PR and take half of its radius 2.8 cm. Take point P as a center and draw an arc by taking the. one diagonal is three times as long as the other, what are the lengths of the diagonals? 62/87,21 The area A of a rhombus is one half the product of the lengths of its diagonals, d1 and d2 Therefore, the diagonals are of length 10.6 cm. and 31.7 cm. $16:(5 10.6 cm , 31.7 cm A trapezoid has base lengths of 12 and 14 feet wit Second, the diagonals of a rhombus are perpendicular bisectors of each other, thus giving us four right triangles and splitting each diagonal in half. We therefore have four congruent right triangles. Using Pythagorean Theorem on any one of them will give us the length of our sides. With a side length of 17, our perimeter is easy to obtain Constructing Quadrilaterals :To construct a quadrilateral, one should know the properties of it .It is constructed using 4 straight sides. Construction of quadrilaterals can be categorized by the length of its sides and the size of its angles A square is a special type of parallelogram whose all angles and sides are equal. Also, a parallelogram becomes a square when the diagonals are equal and right bisectors of each other. Important formulas for Squares. If 'L' is the length of the side of a square then length of the diagonal = L √2. Area = L 2. Perimeter = 4L; Rhombus

In other words, area of a rhombus is half the product of its diagonals. Example 2: Find the area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm. Solution: Area of the rhombus = 1 2 d 1 d 2 where d 1, d 2 are lengths of diagonals. = 1 2 × 10 × 8.2 cm 2 = 41 cm2. A parallelogram is divided into two congruent triangles by drawing a. Construct a rhombus whose diagonals are 6.2 cm and 8.4 cm. 5. Construct a quadrilateral BEST, given ES= 4.5cm, BT= 5.5 cm, St= 5 cm, the diagonal BS= 5.5 cm and diagonal ET= 7 cm. Find Angle E, Angle T and RE Construct a rhombus when the length measures of the diagonals are 8 cm and 6 cm. Draw a rhombus whose side is 7. Note: In the above questions of constructing worksheet on different types of quadrilaterals, first we draw a rough sketch of the required quadrilateral and write down the given dimensions, then explain the steps of construction and. Hint: a 3,4,5 sided triangle is the smallest integer right triangle. The area of a rhombus is equal to half the product of its diagonals. ABCD is a rhombus. Opposite. Construct a triangle PQR, where Angle QPR = 90 degree, PQ = 6 cm and RQ = 7cm Step of construction of Right Angled Triangle, whose length of hypotenuse and one side are given: Step 1: Use ruler and draw a line segment PQ of 6cm (as shown below): Step 2: Use protractor and draw angle of 90 degree at point P (as shown below)

1 16 CONSTRUCTION OF QUADRILATERALS Q1. Construct a quadrilateral WXYZ, such that WX = 3.3 cm, XY = 2 cm, YZ = 2.6 cm, WZ = 1.6 cm and WY = 2.9 cm. Q2. Construct a. The area of a triangle above is given by½b×hSo, Area = ½× 8cm× 6cm × sin 45°=24cm 2 × sin45°= 16.97cm 2 Therefore the area of ABC = 16.97cm 2 Area of a Rhombus The Formula for Finding the Area of Rhombi in Terms of the DiagonalsDerive the formula for finding the area of rhombi in terms of the diagonals.The area of a rhombus is the same as the area of a parallelogram because rhombus is.

SU = 11cm and TV =6cm. Show all construction lines clearly. b) Measure and state the magnitude of angle: (i) STU (ii)SVU State your observation. c) Measure and state the length of : (i) TU (ii)VU d) Let the point of intersection of the diagonals be represented by O. Examine: (i)Δs SOT and SOV (ii)Δs TOU and VOU State your observations 2. **Construct** **a** parallelogram, one of whose sides is 7.2 cm and whose **diagonals** **are** 8 cm and 8.4 cm. Steps of Construction: Firstly, draw a rough figure of the quadrilateral with the given dimensions. 1. Draw a line segment of **length** 7.2 cm and mark the ends as P and Q. 2. Take the point P as a center and draw an arc by taking the radius 4.2 cm. 3